Question

3. A car has initial velocity of 72 km/h. It is accelerated
at 2 m/s2. Calculate the final velocity and the
distance covered after 3
seconds.​

Answer 1

Answer:

U = 72×5/18 m/s = 20 m/s

a = 2 m/s2

V = U+ at

V = 20 + 3×2 = 26

S= Ut + 1/2at2

= 20×3 + 1/2×2×(3)^2

= 60 + 9

= 69

Answer 2

$\Large{\underline{\underline{\bf{GIVEN:-}}}}$

• Initial Velocity (u) of car = 72 km/hr
• Acceleration (a) = 2 m/s²
• Time taken by the car (t) = 3 seconds

$\Large{\underline{\underline{\bf{TO \: FIND:-}}}}$

• What is the final velocity and distance covered by the car ?

$\Large{\underline{\underline{\bf{SOLUTION:-}}}}$

We have given that, the initial Velocity (u) of car is 72 km/hr

Convert the initial Velocity into m/s:-

➛ Initial velocity = $\sf{ 72 \times \dfrac{5}{18}}$

➛ Initial velocity = 20 m/s

To find the final velocity of car, we use the First equation of motion:-

⠀⠀✰ ❮ v = u + at ❯ ✰

According to question:-

➛ v = 20 + 2 $\times$ 3

➛ v = 20 + 6

⠀⠀⠀❛ v = 26 m/s ❜

• FINAL VELOCITY = 26 m/s

To find the distance covered by the car, we use the second equation of motion:-

✰ ❮ s = ut + $\bf{\dfrac{1}{2}}$ at² ❯ ✰

According to question:-

➛ s = 20 $\times$ 3 + $\sf{\dfrac{1}{2}}$ $\times$ 2 $\times$ (3)²

➛ s = 60 + 9

⠀⠀⠀❛ s = 69 m ❜

• DISTANCE = 69 m

❝ Hence, the final velocity of car is 26 m/s and distance covered by car is 69 m ❞

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