Question

3) A car is moving with a uniform acceleration of 12m/s2. If the car
takes 3s to stop after the application of breaks, calculate the
distance it travels during this time.
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Answer 1

Answer:

Here is your answer

Explanation:

Acc=12m/s

Time=3sec

Initial velocity=?

Final velocity =0

So, acc=v-u/t

Acc=u/3

12*3=0-u

36=u

S=?

Acc=12

Initial velocity =36

Time=3sec

So,s=ut+1/2at²

S=36*3+1/2*12*3²

S=108+1/2*108

S=108*54

S=5832m

If I am right so mark me as brainlist

Answer 2

Explanation:

First, we need to find the total distance.

So,

Total distance (D) = D₁ + D₂

⟹ 20m + 30m

⟹ 50m

Now, we need to find the total time taken.

So,

Total time taken (T) = T₁ + T₂

⟹ 3s + 4s

⟹ 7s

Now, we need to find the average speed of the object,

So,

$average \: speed = \frac{total \: time \: taken}{total \: distance}$

$\frac{50}{7}$

⟹ 7.14286 m/s

Hope this may helps u dear..✌️