Question

3. A car is moving with a velocity of 36 km/h on a
straight road. On the application of the break it
comes to rest after covering a distance of loom. Calculate
the deceleration of the car.​

Answer 1

formula :v^2=u^2-2as

v=0, u=36, s=100

ans=a=(u^2-v^2)÷2s=36^2÷200= 6.48 m/s^2