Question

3 A car of mass 1000kg & bus of
1000ks are morning with the same velocity
of 36 km/h . Find the force to stop both
the car & the Bus in 5s.​

Answer 1

Answer:

16000N

Explanation:

=Initial velocity =36km/h

=Final velocity =0m/s

=Time =5 sec

'=u+at

=O=10+a*5

=a=-2 m/s2

The force to stop both car in 5s

=ma

=1000*2=2000

The force to stop both the bus in 5s

=ma

=1000*2=2000

Hope it helps...

Answer 2

$\huge\sf\pink{Answer}$

☞ Force applied will be -4000 N (i.e force is in the opposite direction)

━━━━━━━━━━━━━

$\huge\sf\blue{Given}$

✭ Mass of both the car & the bus (m) = 1000 kg

✭ Initial Velocity (u) = 36 km/h

✭ Final Velocity (v) = 0 m/s

✭ Time (t) = 5 sec

━━━━━━━━━━━━━

$\huge\sf\gray{To \:Find}$

◈ The Force required in total?

━━━━━━━━━━━━━

$\huge\sf\purple{Steps}$

We shall first convet the Initial Velocity from km/h to m/s

➢ $\sf 36 \times \dfrac{5}{18}$

➢ $\sf v =10 \ m/s$

So now let's find the acceleration with the help of the first equation of motion, that is,

$\underline{\boxed{\sf v=u+at}}$

Substituting the values,

➳ $\sf 0 = 10+a\times 5$

➳ $\sf -10 = 5a$

➳ $\sf \dfrac{-10}{5} = a$

➳ $\sf \green{a = -2 \ m/s}$

We know that,

$\underline{\boxed{\sf F = ma}}$

Substituting the values,

➝ $\sf F = 1000\times -2$

➝ $\sf \red{F = -2000 N}$

So we found the force applied for one body but here we are given two bodies of equal mass,so

»» $\sf F_{net} = -2000+(-2000)$

»» $\sf \orange{F_{net} = -4000 \ N}$

━━━━━━━━━━━━━━━━━━