Question

3. A car of mass 1800 kg moving with a speed of 10 m s-l is brought to rest after covering a
distance of 50 m. Calculate the force acting on the car.​

Answer 1

Answer:

Correct option is

A

1800 N

Given,

M=1800kg

u=10ms

−1

s=50m

F=?

We know that

V

2

−u

2

=2as

0−(10)

2

=2a×50m

a=

100

−100

=−1ms

−2

F=ma

Therefore, deceleration=−1m/s

2

Deceleration=−(acceleration)

F=1800×1ms

−2

=1800N

Force will be acting in the opposite direction to a displacement of the car

Answer 2

Step-by-step explanation:

this is your answer!

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