Question

3) A car starts from rest & moves along x-axis with constant acceleration 5 ms for 8
seconds .If it
then continues with constant velocity, what distance will the car cover in 12
seconds since it started from the rest?​

Answer 1

Answer:

here it is.....

Explanation:

GIVEN,

Initial velocity(u)=0m/sec

acceleration(a)=5m/sec square

time=12 sec

s=ut +1/2 at square

s=0*8+1/2*5*144(square of 12)

s=0+5*72

s=360 m ans

HOPE IT WOULD HELP........