Question

3. A car travels at 20 ms -1. After it travels 60 m its velocity is 40 ms. Its acceleration is
a) 10 ms-2 b)16.67 ms-2 c) 20 ms-2
d)1.667 ms-2​

Answer 1

Answer:

a) 10m/s²

Explanation:

Initial velocity = u = 20m/s

Final velocity = v = 40m/s

Distance = s = 60m

Acceleration = ?

According to 3rd law of motion

v²-u² = 2as

Replacing the values

40²-20²= 2*60*a

= 1600-400 = 120a

= 1200 = 120a

= a = 1200/120

= a = 10m/s²

Hope it helps

Answer 2

in this initial velocity is u =20m /s

final velocity v= 40 m/s

distance s=60

so we know that

2as = v2- u2

2a(60) = 1600 - 400

120a=1200

a = 1200/120

a= 10m per second