3.
A charge particle after being accelerated
through a potential difference V enters in a
uniform magnetic field and moves in a circle
of radius r. If V is doubled, the radius of the
circle will become
(a) 2 r
(b) V2r.
(c) 4r
(d) r/v2
(2020)
Answers
Answered by
2
Answer:
√2r (why don't I see this option?)
Explanation:
radius r=mv/qB
=√(2mqV)/qB where V is potential through which q is accelerated
r is proportional to root of V
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