Question

3. A chord AB of the larger of the two concentric circles is tangent to the smaller circle at point P. Show that point P is the mid-point of AB. ​

Answer 1

This is your answer i hope it helps

Answer 2

Answer:

The proof is given below.

Step-by-step explanation:

See the attachment below for reference.

Given:

AB is the chord of larger circle.

AB is tangent of the smaller circle at P.

To show:

P is the mid point of AB

=> AP = PB

Construction:

Construct a perpendicular from O to P.

Proof:

We know that the the line perpendicular to a chord, bisects the chord.

Therefore, using this theorem,

As OP is perpendicular to the chord AB,

It bisects the chord AB

=> AP = AB

Hence, the result.