Question

3. A circle has its center at ( 3, 2) and one of the diameter at ( 7,2 ). Find the other end of the diameter

Answer 1

ANSWER: (-1,2)

EXPLAINATION :

THERE IS A FORMULA,

(x,y)=(x1+x2) + (y1+y2)

2 2

.: (3,2)=(7+x2) + (2+y2)

2 2

.: 3×2=7+x2 and 2×2=2+y2

.: x2= 6-7 and y2= 4-2

.: (x2,y2) = (-1,2)

.: THE OTHER END OF DIAMETER IS (-1,2).