Question

3. A circular sheet of diameter 16 cm is cut off from a rectangular metal sheet of dimensions
35 cm by 45 cm. Find the area of the remaining metal sheet. (Take te=3.14)​

Answer 1

Answer:

1374.04 cm^2

Step-by-step explanation:

The area of remaining metal sheet= area of rectangle - ata of circle

A= l×b - πr^2

A= 35×45 - 3.14×8^2

A= 1575 - 200.96

A= 1374.04 cm^2

Answer 2

Given :

• The diameter of a circular sheet =16cm

• It is cut off from a rectangular metal sheet of dimensions =35 cm by 45cm

To find :

• The area of the remaining metal sheet =?

Formula :

$\red \bigstar \boxed{ \tt{diameter = \frac{radius}{2} }}$

$\red \bigstar \boxed{ \tt{area \: of \: rectangle = length \: \times breadth}}$

Solution :

•The diameter of a circular sheet =16cm

$\\ \implies \bf \: diameter = \frac{radius}{2}$

$\implies \sf \: diameter \:o f \: sheet = \pi {r}^{2}$

$\implies \sf \: diameter \: of \: sheet = \pi {(8)}^{2}$

$\\ \implies \sf \: diameter \: of \: sheet = 3.14 \times 8 \times 8$

$\\ \implies \boxed{ \bf{diameter \: of \: sheet = 200.96 {cm}^{2} }}$

•Length =35cm

•Breadth=45cm

$\\ \implies \sf \: area \: of \: rectangle = length \times breadth$

$\implies \sf \: area \: of \: rectangle = 35 \times 45$

$\\ \implies \boxed{ \bf{area \: of \: rectangle = 1575 {cm}^{2} }}$

$\\ \therefore \sf \: required \: area = area \: of \: rectangle - area \: of \: circular \: sheet$

$\\ \implies \sf \: required \: area = 1575 - 200.96$

$\\ \implies \boxed{ \bf{required \: area = 1374.04}}$

The area of remaining metal sheet is 1374.04cm²