Question

3.A compound has the composition :-
Na = 29% S=405 % and 0 = 30.5%.2f the
formula mass is 158, what is the fornula mount
of the compound​

Answer 1

Answer:

For this we make table as:

Element

%Composition

Atomic Mass

Molar Ratio

Simple Ratio

Na

29.11%

23

(29.11/23)

(1.266/1.266)=1×2=2

S

40.51%

32

(40.51/32)

(1.266/1.266)=1×2=2

O

30.38%

16

(30.38/16)

(1.898/1.266)=1.5×2=3

∴ Formula is Na2S2O3