Question

3. A conductor moving with a speed of 20 m/s in the direction perpendicular to the
direction of magnetic field of induction 0:5 T, induces an EMF of 5 V. The length of theof the conductor is
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Answer 1

Induced emf(E) = Bvl

5 = 0.5 × 20 × l

l = 0.5m

Hope this helps you!!

Answer 2

Answer:

$\boxed{\mathfrak{Length \ of \ the \ conductor = 0.5 \ m}}$

Given:

Speed (v) = 20 m/s

Magnetic field (B) = 0.5 T

Induced\Motional EMF (ε) = 5 V

Explanation:

Formula of Induced\Motional EMF:

$\boxed{ \bf{ \epsilon = Blv}}$

l → Length of the conductor

By substituting values in the formula we get:

$\rm \implies 5 = 0.5 \times 20 \times l \\ \\ \rm \implies 10l = 5 \\ \\ \rm \implies l = \frac{5}{10} \\ \\ \rm \implies l = \frac{1}{2} \: m \\ \\ \rm \implies l = 0.5 \: m$