3. A coolie raises a box of mass 50 kg to a vertical height of 3 m. Calculate the work done by the coolie if force of gravity on 1 kg mass is 10 N.
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Consider the following,
work done is written as W = F.s = FsCosθ here F is the force applied, s is the displacement caused such that
F = mg = 10 X 10 = 100 N s
W( horizontal direction)= FsCos(0)=500J , θ is the angle between (vectors) F and s now,
as F and s are perpendicular for vertical direction, θ = 90 thus, W = FsCos90 = 0
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