3. A copper wire of 10-m’ area of cross
section, carries a current of 2 A. If the
number of free electrons per cubic
meter in the wire is 8 x 1028, calculate
the current density and average drift
velocity of electrons.
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volt,
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Answer:
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Explanation:
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Answer:
Explanation:
Cross-sections area of copper wire, A = 106 m2 I = 2 A
Number of electron, n = 8 x1028
Current density, J = 1/A = 2/10−6 J = 2 x 106Am-2
Average drift velocity, Vd = 1/neA
e is the charge of electron = 1.6 × 10-9 C
vd =2/8 ×10 28×1.6×10 -19×10 -6
vd =1/64×103
Vd = 0.15625 x 10-3
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