Question

3. A copper wire of 10-m’ area of cross
section, carries a current of 2 A. If the
number of free electrons per cubic
meter in the wire is 8 x 1028, calculate
the current density and average drift
velocity of electrons.
esent
volt,
nduct​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Explanation:

Cross-sections area of copper wire, A = 106 m2 I = 2 A

Number of electron, n = 8 x1028

Current density, J = 1/A   = 2/10−6    J = 2 x 106Am-2

Average drift velocity, Vd = 1/neA

e is the charge of electron = 1.6 × 10-9 C

vd =2/8 ×10 28×1.6×10 -19×10 -6

vd =1/64×103                                          

Vd = 0.15625 x 10-3