Question

3. A cricket ball of mass 200g is moving with a speed of 10 ms. A player stops it in 0.04 seconds. Find the retardation produced and the retarding force of the hand​

Answer 1

Mass=200g=0.2kg

Initial velocity (u) =10m/s

Time taken = 0.04seconds

Final velocity (v) =0m/s

Using the eq. a=v-u/t

=>a=0-10/0.04

=>a= -250m/s

That's the Answer