Question

3. A current of 4 amp flows in a wire of resistance 60 2. Calculate:
(a) Power dissipated in the wire.
(b) Potential difference across the wire.
(c) Electrical energy consumed in 2 minutes.​

Answer 1

Answer:

i am taking the resistance as 60 ohm as it is not very clear in the question.

Explanation:

I = 4 A

R = 60 OHM

A). P = I∧2×R (formula of power or the relation between power,current and resistance)

we will put the values

P=4∧2×60=16×60=960 W

B).we know that,

V=IR

we will put the respective values,

I=4A

R=60 OHM

V=IR

V=4×60=240V

C).electrical energy

as we have already calculated power so we can simply divide power by the time given

Time= 2 Mins= 120 seconds

electrical energy = POWER/TIME=960/120=8 WATT PER SECOND

ANY QUERRY WILL BE ANSWERE IN COMMENT SEC