Question

3) A cyclist is moving with a speed of 14 m/s. He starts accelerating with
a rate of 6 m/s2 and acquired the speed of 18 m/s. Calculate, what
distance did he move in acquiring that speed?
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Answer 1

Answer:

10.67 m distance acquiring to achieve speed 18 m/s

Step-by-step explanation:

v1=14 m/s

a=6 m/s^2

v2=18 m/s

s=distance?

use formula , v2^2=v1^2+2as

18^2=14^2+2*6*s

324=196+12s

12s=324-196

12s=128

s=. 128 /12

s=10.67m

Answer 2

sᴏʟᴜᴛɪᴏɴ :-

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ɪɴɪᴛɪᴀʟ ᴠᴇʟᴏᴄɪᴛʏ => 14 m/s

ғɪɴᴀʟ ᴠᴇʟᴏᴄɪᴛʏ => 18 m/s

ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ => 6 m/s^2

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ᴜsɪɴɢ ᴛʜɪʀᴅ ᴇǫᴜᴀᴛɪᴏɴ ᴏғ ᴍᴏᴛɪᴏɴ

v^2 - u^2 = 2as

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(18)^2 - (14)^2 = 2 × 6 × S

324 - 196 = 12s

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128 / 12 = S

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S = Distance = 10.67 meter

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#Ayush1abhigyan

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