Question

3. A fair dice is thrown thrice. Find the probability that the sum of the
numbers obtained is 10.​

Answer 1

Answer:

$Probability of a sum of 10: 27/216 = 12.5%$

Answer 2

Answer:

The total number of cases is 63=216

Now,the number of solutions of the equation x+y+z=9 with each of x,y,z greater than equal to 1 is (82).