Question

3. A father is 7 times as old as his son. Two years ago, the father was 13 times as old as
his son. What are their present ages!
​

Answer 1

Answer:

son age = 4

father age = 28

Step-by-step explanation:

let son age = x

father age = 7x

2 year ago

son age = x-2

father age = 7x-2

as given

13(x-2) = 7x--2

x = 4

son age = 4

father age = 28

Answer 2

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

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$\large{\green{\underline \bold{\tt{Given :-}}}}$

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• Father is 7 times as old as his son

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• Two years ago, father was 13 times as old as his son

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$\large{\red{\underline \bold{\tt{To \: Find :-}}}}$

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• Their present ages

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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• Let the present age of father be "f"

• Let the present age of son be "s"

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$\purple{\underline \bold{According \: to \: the \ question :}}$

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〚 Father is 7 times as old as his son 〛

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➠ f = 7s ------ (1)

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$\underline{\bold{\texttt{Father's age 2 years ago :}}}$

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➠ f - 2

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$\underline{\bold{\texttt{Son's age 2 years ago :}}}$

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➠ s - 2

$\:\:$

〚 Also given that ,two years ago, father was 13 times as old as his son 〛

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So,

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➠ f - 2 = 13(s - 2)

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➜ f - 2 = 13s - 26

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➜ f = 13s - 26 + 2

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➜ f = 13s - 24 -------- (2)

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$\underline{\bold{\texttt{Putting f = 7s from (1) to (2) }}}$

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➜ f = 13s - 24

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➜ 7s = 13s - 24

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➜ 24 = 13s - 7s

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➜ 6s = 24

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➜ $\sf s = \dfrac { 24 } { 6 }$

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➨ s = 4 ----- (3)

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• Hence son's present age is 4 years

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$\underline{\bold{\texttt{Putting s = 4 from (3) to (1) }}}$

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➠ f = 7s

$\:\:$

➜ f = 7(4)

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➨ f = 28

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• Hence father's present age is 28 years

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Therefore the present ages of father and son are 28years & 4 years respectively