Question

3. A father is four times his son's age. 7 years ago he
was 11 times his son's age. Find the present ages of
father and son.​

Answer 1

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➙ Son's age = 10 years

➙ Father's age = 40 years

$\blue{\underline{\underline{\purple{\mathbb{SOLUTION:-}}}}}$

★ Given that ,

The present age of father is 4 times that of the son .

so , let the son's age be x , according to Question , father's age will be '4x'

Before 11 years the father's age would be 4x - 11 years and that of son would be x - 7 years .

so ,

★According to the question :

➙ 4x - 7 = 11 ( x - 7 )

➙ 4x - 7 = 11x - 77

➙ 4x - 11x = -77 + 7

➙ -7x = 70

➙ x = 70/7

➙ x = 10

$\therefore$ Age of son = x = 10 yrs

Age of father = 4x = 10 × 4 = 40 years .

Hence Done✔

Answer 2

Answer:

father 40 years. son 10 years

Step-by-step explanation:

According to the question :

➙ 4x - 7 = 11 ( x - 7 )

➙ 4x - 7 = 11x - 77

➙ 4x - 11x = -77 + 7

➙ -7x = 70

➙ x = 70/7

➙ x = 10

\therefore∴ Age of son = x = 10 yrs

Age of father = 4x = 10 × 4 = 40 years .