Math, asked by gunnusandhu28sep, 5 months ago


3. A father's age is 3 times the sum of ages of his two sons. Five years later he will be twice the sum of ages of his two sons . find the present age of the father​

Answers

Answered by bponna2006
2

Answer:

Given that Father's age is three times the age of his two sons. Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son. Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5. Thus the age of the father is 45.

Answered by arunabalamohapatra
1

Answer:

Given that Father's age is three times the age of his two sons. Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son. Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5. Thus the age of the father is 45.

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