3. A field in the form of a parallelogram has base 200 m and altitude 80 m long. Find the cost of watering the field at Rupees 1per 100m².
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Answer:
160 rupees
Step-by-step explanation:
base = 200 m
altitude =80 m
area of parallelogram =b×h
= 200×80
=16000 m²
cost of watering per 100 m² = 1 rupee
cost of watering per m² = 1/100 rupee
cost of watering 16000 m² = 16000×1/100
= 160 rupees
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