Question

3. A force acts on a particle of mass 200 g. The velocity of the particle changes from 15 ms-' to 25 ms in 2.5 s. Assuming the force to be constant, the magnitude of force is [ ] a) 8 N b) 0.8 N c) 0.08 N d) 80 N​

Answer 1

Answer:

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Explanation:

Correct option is

b)

0.8 N

a=

Δt

Δv

=

2.5

25−15

=4ms

−2

F=ma=0.2×4=0.8N

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Answer 2

Answer:

a= ∆v/∆t

=25-15/2.5

=4ms^-2

F=ma=0.2×4=0.8N

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