Question

3. A force of 10N is making an angle of 30° with the x- axis. Its horizontal component will be??

Answer 1

hello mate,

horizontal component is the force that is applied as a result of the diagonal application of force.

here in this case,

given diagonal force =10N.

angle= 30°

horizontal component is found using trigonometry..

so,

A vector of magnitude 10 N is provided.

It is at an angle of 30° to the + x axis.

To find:

The components along the x and y axis.

Calculation:

Along x axis:

F(x) = F cos(θ)

=> F(x) = 10 × cos(30)

=> F(x) = 10 (√3/2) = 5√3N

Along y axis:

F(y) = F sin(θ)

=> F(y) = 10 sin(30°)

=> F(y) = 10 × ½

=> F(y) = 5 N.

Additional information:

1. A vector is a quantity that can be defined with both magnitude and direction.

2. Since force is a vector, we are able to break it down into components along chosen axis.

hope this helps you.

pls mark it brainliest

Answer 2

Vertical element is the force that's applied as a result of the slant operation of force.

then in this case,

given slant force = 10N. angle = 30

vertical element is set up using trigonometry.

So,

A vector of magnitude 10 N is handed.

It's at an angle of 30 ° to the x axis.

To find

The factors along the x and y axis.

computation-

Along x axis-

F( x) = vdash cos( θ)

= > F( x) = 10cos( 30)

= F( x) = 10( √/ 2) = 5 √ 3N Along y axis

F( y) = F × sin( θ)

= > F( y) = 10 sin( 30)

= > F( y) = 10 ×1/2

= > F( y) = 5N

fresh information

1. A vector is a volume that can be defined with both magnitude and direction.

chosen axis.

2. Since force is a vector, we're suitable to

break it down into factors along

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