3. A force of 150 N acts on a particle at an angle of 30° to the horizontal.
Find the horizontal and vertical components of force.
kamples.
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This explanation from Physics/Geometry
60o |
|
| Fy (the vert. comp.)
↑
← 30o |
Fx (the horizontal componenet)
F = √(Fx2 + Fy2)
Fy = 50 · cos 60o = 50 · (1/2) = 25 N
Fx = 50 · cos 30o = 50 · (√3)/2 = 25√3 N
I see, that vector sign did not appear in my comment above, so the vector equation is
→ → →
F = 50 cos 30o i + 50 cos 60o j
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Answer:
this is correct in equstion
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