Question

3) A force of 20N acts on a body. If the displacement of the body is 0.6m in the
direction opposite to that of the force, calculate the work done by the force​

Answer 1

GIVEN:

• Force = 20N
• Displacement (s) = 0.6 m.

TO FIND:

• Work done.

SOLUTION:

$\to \sf{\red{W=fs}}$

Where:

• f is force.
• s is displacement.

Substitute.

$\to \sf W=20 \times 0.6$

$\leadsto \sf{\red{W=12 \ J}}$

WORK DONE - 12 J.

Kinematic equations:

$\boxed{\substack{\displaystyle \sf v=u+at \\\\ \displaystyle \sf s=ut+\dfrac{1}{2}at^2 \\\\ \displaystyle \sf 2as=v^2-u^2 }}$

Regards,

Sujal Sirimilla

ex brainly star