Question

3. A hammer having a mass of 1 kg going with a speed of 6 m/s hits a wall and comes to rest in
0.1 sec. Compute the obstacle force that makes the hammer stop?​

Answer 1

ᴘᴀɴᴛʜᴇʀɪᴏ's ʀᴇsᴘᴏɴsᴇ:-

Given:-

• Initial velocity (u) = 6 m/s
• Final velocity (v) = 0 m/s [Since it will come to rest]
• Time taken (t) = 0.1 second
• Mass of the hammer (m) = 1 kg

To Find: Force exerted by the obstacle to the hammer to make it stationary.

We know,

• F = ma
• a = (v - u)/t

where,

• F = Force,
• m = Mass,
• a = Acceleration,
• v, u = Final and initial velocities respectively,
• t = Time taken.

∴ F = (1 kg){[(- 6) m/s]/0.1 s}

⇢ F = (1 kg)[- 6 m/s]/(1/10 s)

⇢ F = (1 kg)(- 60 m/s²)

⇢ F = - 60 N

(Force in the direction of motion)

REQUIRED ANSWER:-

➯ The obstacle provided a force of 60 N on the hammer.