Question

3) A hammer having a mass of 1 kg going with a speed of 6 m/s hits a wall and comes to rest in 0.1 sec. Compute the obstacle force that makes the hammer stop.​

Answer 1

To Find :-

• Compute the obstacle force that makes the hammer stop.

Solution :-

Given,

• Mass of Hammer (m) = 1 kg
• Initial Velocity (u) = 6 m/s
• Final Velocity (v) = 0 m/s
• Time Taken (t) = 0.1 s

Acceleration :- The rate of change of velocity per unit of time.

Mathematically,

${ \orange{ \bold{a = \frac{v - u}{t} }}} \: \bigstar$

Where,

• u = Initial velocity
• v = Final velocity
• t = time taken

[ Putting values ]

$\longrightarrow \sf \: a = \frac{0 - 6}{0.1}$

$\longrightarrow \sf \: a = \frac{ - 6}{0.1}$

$\longrightarrow \sf \: a = - 60 \: ms {}^{ - 1}$

[ Note :- -ve sign indicates retardation]

$\longrightarrow \sf \red{ a = 60 \: ms {}^{ - 1} }$

Now,

Force :- The product of mass (m) and acceleration (a).

Mathematically,

$\pink {\bold{F = ma}} \: \bigstar$

Where,

• m = mass
• a = acceleration

[ Putting values ]

$\longrightarrow \sf \: F = 1 \times 60$

$\longrightarrow \sf \green{ F =60 \: N }$

Therefore,

A retarding force that stops a hammer is 60 N.