Question

3.A heap of rice is in the form of cone of
diameter 12m and height 8m. Pind its volume?
How
much canvas cloth is required to cover the
heap ? (use = 3.14)​

Answer 1

Answer:

Therefore, 188.4 square meter cloth is required to cover the heap.

Answer 2

Answer :-

Volume = 301.44m

Curved surface area = 188.4m^2

Explanation :-

Given :

Diameter (d) = 12m

Height (h) = 8m

To Find :

Volume = ?

How much canvas is required to cover the heap = ?

Solution :

Radius (r) = 12/2m

∴ 6m

Volume of a cone,

$\boxed{\sf{}\dfrac{1}{3}\pi r^2h}$

Put their values and solve it

$:\implies \sf{}\dfrac{1}{3}\times 3.14\times 6\times 6\times 8$

$:\implies\sf{}\dfrac{1}{3}\times 904.32$

$\therefore\sf{} 301.44m^2$

Therefore, volume is equal to 301.44m^2.

Canvas require to cover the heap is equal to the curved surface area of heap which is in cone shape.

Curved surface surface area of the cone,

$\boxed{\sf{}\pi rl}$

We do’t know the value of “l” which is the slant height, so let’s find it first.

$\sf{}l^2=r^2+h^2$

$\sf{}:\implies l^2=6^2+8^2$

$\sf{}:\implies l^2=36+64$

$\sf{}:\implies l^2=100$

$\sf{}\therefore l=10m$

So,curved surface area:

$:\implies \sf{}3.14\times 6\times 10$

$\therefore \sf{}188.4m^2$

Therefore,188.4m^2 cloth is required to cover the heap