Question

3.) A line segment AB= 8cm is divided in the ratio 3:2 by a ray at point P' lies on AB.
The distance of point P' from 'A' is​

Answer 1

The length of AP' is 4.8 cm.

Step-by-step explanation:

It is given that a line segment AB= 8cm is divided in the ratio 3:2 by a ray at point P' lies on AB.

Point P' lies on the line segment AB. It means point P' divides the line AB in two parts AP' and P'B.

Let length of AP' and P'B are 3x and 2x respectively.

$AB=AP'+P'B$

$8=3x+2x$

$8=5x$

Divide both sides by 5.

$\frac{8}{5}=x$

The value of x is 8/5.

The length of AP' is

$AP'=3x=3\times \frac{8}{5}=4.8$

Therefore, the length of AP' is 4.8 cm.

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Answer 2

Answer:

Step-by-step explanation:

Given that ab=8cm divided into 3:2 ratio by a ray at point p' lies at ab.

it means that p'divides ab into two parts ap' and p'b

let length of ap' and p'b are 3x and 2x

AB=AP'+P'B

8=3X+2X

8=5X

X=8/5

AP'=3X=3 X 8/5= 24/5=4.8

AP'=4.8