Question

[3]
A liquid of mass m and specific heat s
is at temperature 0. Another liquid of mass 2m
andspecific Heat s/2 is at 30.
If these two liquids are mixed, the resultant
temperature of themixture is
0/2
0
106-2
20
1107-2 Σ
O 30/2
108 -2
109​

Answer 1

Answer:

Explanation:

θ=  

m  

1

​  

S  

1

​  

+m  

2

​  

S  

2

​  

 

m  

1

​  

S  

1

​  

θ  

1

​  

+m  

2

​  

S  

2

​  

θ  

2

​  

 

​  

 

=  

(m×S)+(m/2×2S)

(m×S×T)+(m/2×2S×2T)

​  

 

=  

2mS

3mST

​  

=  

2

3

​  

T

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