Question

3. A lot of 60 bulbs contain 12 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective? Suppose the bulb drawn in first attempt is defective and is not replaced. Now, one bulb is drawn at random from the rest. What is the probability that this bulb is not defective​

Answer 1

Answer:

Step-by-step explanation:

given no. of bulbs = 60

out of defective ones = 12

so probability of getting defective bulb =      no. of bulbs

                                                                    --------------------------------  = 12/60 = 1/5

                                                                   no. of defective  bulbs

i hope that's the answer to the question

thanks

Answer 2

Answer:the probability of drawing a defective bulb 1/5 and the probability of drawing a non defective bulb will be 49/59

Step-by-step explanation: n(A)=12

P(A)= n(A)/n(S)

12/60

1/5

n(S) now equals to 59 and n(B)= 60 - 11

n(B) = 49

P(B) = n(B)/n(S)

49/59