3. A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:(please answering with details)
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Answered by
0
Answer:
Step-by-step explanation:
1. he would have taken 40 minutes less if speed was 3kmph more
2.If he had moved 2 kmph slower, he would have taken 40 minutes more
now, Distance =S1S2S1−S2×t
from both conditions,
S(S+3)3×40=S(S−2)2×40
2S+6=3S−6
S = 12 km/hr
from condition 1st
12×153×4060 = 40 km
Answered by
0
Answer:
40-KM
Step-by-step explanation:
d1 = d2
s*(s+3)*40/3=s*(s-2)*40/2
s=12
put value of s in equation of d:
d=s*(s+3)*40/3*60...divide by equation by 60 to convert minute into hour
d = 40-KM
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