Question

3. A man goes 20 m due west and then 15 m due
North. How far is it from the starting point?
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Answer 1

Answer:

Here , the man moves 20 m due west and then 15 m due North. So , his net displacement is due north - west . => AC = 25 m . Thus , he is 25 m far away from the starting point .

Answer 2

distance b/w starting point =(20*20)*+(25*25)=625

as we know 625 Is a square of 25 Therefore, distance from starting point is 25m

hope it will help u!!!!

Step-by-step explanation:

In the above Question , the following information is given -

A man goes 20 m due west and then 15 m due North.

To find -

Find his distance from the starting point.

Solution -

See the above attached image .

Here , the man moves 20 m due west and then 15 m due North.

So , his net displacement is due north - west .

Required Displacement can be calculated by Pythagoras theorem -

AC = √ ( AB )² + ( BC )²

=> AC = √ ( 15 )² + ( 20 )²

=> AC = √ ( 225 + 400 )

=> AC = √625

=> AC = 25 m .

Thus , he is 25 m far away from the starting point .

This is the required answer .