Math, asked by sjhaShivam9826, 7 months ago

3.A man has a wife, two sons and three daughters. His property of Rs. 10, 60, 000 is divided among them in such a way that the ratio of the share of his wife to daughter is 5 : 2, and that of his wife to son is 3 : 2. Find the share of his each son. a) Rs. 3, 00, 000 b) Rs

Answers

Answered by vidhurideepak0
0

Step-by-step explanation:

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Answered by tanvigupta426
0

Answer:

The share of the son is 400000$.

Step-by-step explanation:

Given:

The property of Rs.10, 60, 000 exists divided among them in such a way that the ratio of the share of his wife to daughter exists 5 : 2, and that of his wife to son exists 3 : 2.

To find the share of each son.

Step 1

Let the ratio of wife $=W$

ratio of daughter $=D$

ratio of Son $=S$

$\Rightarrow S: D=5: 2=15: 6$

$\Rightarrow W: S=3: 2=15: 10$

$\Rightarrow W: D: S=15: 6: 10$

Step 2

He has a wife 2 sons and 3 daughters

$\Rightarrow W: D: S=15: 6 \times 3: 10 \times 2

=15: 18: 20$

So, the share of the son

$=1060000 \times \frac{20}{15+18+20}

=400000$

Therefore, the share of the son is 400000$.

#SPJ2

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