Question

3.
A man standing in front of a large wall, claps two
objects against each other at an interval of 1.2 s
regularly. The echo of the first clap coincides
with the fifth clap. If the speed of sound in air
is 340 m s -1, the distance between the man and
the wall is
(a) 408 m
(c) 816 m
(b) 1632 m
(d) 204 m​

Answer 1

Answer-

(c) 816 m

Explanation:

According to the question, echo of the first clap coincides with the fifth clap.

Interval of the clap, t, 1.2 s

First echo is heard at time,

$\sf{t_2}=(5-1)t,=4×1.2 = 4.8 s$

Let distance between man and the wall be d.

Speed of sound,$\sf{v=340 m/s}$

$\sf{v=\dfrac{d+d}{t_2}=\dfrac{2d}{t_2}}$

$\sf\implies{d=\dfrac{v×{t_2}}{2}=\dfrac{340×4.8}{2}=816\:m}$

Answer 2

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