Question

3. A measuring cylinder contains 50 ml water. When a stone of mass 60 gm is lowered into the measuring cylinder, the water level rises to 70 ml. Calculate the density of the stone.​

Answer 1

Answer:

volume 1 =50 ml

Volume 2= 70 ml

Volume =V 2 - V 1

=70-50

= 20 ml

1ml = 1cm^3

20ml = 20cm^3

mass =60 gm

Volume =20cm^3

density = mass / volume

= 60 / 20

= 3 g/cm^3

Answer 2

Answer: 2.5 g/cm*3

Explanation:-

To calculate the density of the stone:-

Density = Mass/Volume i.e D = M/V

1. Note the initial volume of water as V1

2. When stone of mass 60gm is lowerd into the measuring cylinde, the water rises to 70ml so let it be V2

3. Find the difference between the initial & final volume of irregular solid

Thus, the volume of irregular solid,

V = V1 — V2

V = 70 — 50

= 20 ml

= 20 cm*3 ( since 1 ml = 1 cm*3 )

Now for finding the density of the stone,

Density = M/V

D = M/V

D = 50/20 = 2.5 g/cm*3