Question

3. A metal rod PQ is placed in
the magnetic field. The ends of
the rod are connected with a
battery using wires. Where will
the rod move?
Magnetic field
Rod
P​

Answer 1

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Induce EMF is e=Blv=9×10

−3

V

The polarity of the induced emf is such that end P shows positive while end Q shows negative ends.

(b)

Yes; when key K is closed, excess charge is maintained by the continuous flow of current.

When key K is open, there is excess charge built up at both ends of the rods.

When key K is closed, excess charge is maintained by the continuous flow of current.

(c)

Magnetic force is cancelled by the electric force set-up due to the excess charge of opposite nature at both ends of the rod.

Answer 2

Answer:

$\huge\fcolorbox{black}{lime}{❥ᴀ᭄ɴsᴡᴇʀ}$

Explanation:

Induce EMF is e=Blv=9×10

−3

V

The polarity of the induced emf is such that end P shows positive while end Q shows negative ends.

(b)

Yes; when key K is closed, excess charge is maintained by the continuous flow of current.

When key K is open, there is excess charge built up at both ends of the rods.

When key K is closed, excess charge is maintained by the continuous flow of current.

(c)

Magnetic force is cancelled by the electric force set-up due to the excess charge of opposite nature at both ends of the rod.

$\huge \colorbox{pink}{❥ᴛʜᴀ᭄ɴᴋs}$