Question

3.A mixed oxide has ccp arrangement in which the cations 'X'occupy 1/3rd
of octahedral voids and the cations 'Y' occupy 1/3rd of tetrahedral
voids.The formula of oxide is:
O (A) X2Y302
O (B) XY30
O (C) X2Y03
O (D) XY203​

Answer 1

Answer:

Given that,

The cations 'X' occupy 1/3rd of octahedral voids and the cations 'Y' occupy 1/3rd of tetrahedral voids.

The effective number of oxide ions = 4

We need to calculate the effective number of cations X

Using formula of effective number

Effective number of Cations (X) = 1/3 × number of octahedral voids

effective number of cations (X) = 1/3 × 8

effective number of cations (X) = 8/3

We need to calculate the effective number of cations Y

Using formula of effective number

effective number of cations Y = 1/3 × Number of tetrahedral voids

effective number of cations Y = 1/3 × 4

effective number of cations Y = 4/3

Hence, The formula of the compound will be A2BO3.

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