3. A number consist of 2 digits whose sum is 9.
It 27 is subtracted from the number it's digit are
reversed. Find the number.
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Step-by-step explanation:
let the unit digit be x
then the tens digit will be 9-x
number obtained = 10(9-x)+x
= 90-9x
now according to question
(90-9x) - 27 = reversed number
90-27-9x = 10x+(9-x)
63-9x = 9x+9
9x + 9x = 63-9
18x = 54
x = 3
Required Number = 90-9×3
= 63
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