Question

3. A number is 4 times another number, If
21 is added to both the numbers then first
number becomes 7/4times the other
number. What are the numbers?​

Answer 1

Step-by-step explanation:

x=4y

(x+21)=7/4(y+21)

4y+21=7/4(y+21)

16y+84=7y+147

9y=63

y=7

x=4×7=28

Answer 2

$\bf{\underline{Question:-}}$

A number is 4 times another number, If

21 is added to both the numbers then first

number becomes 7/4times the other

number. What are the numbers?

$\bf{\underline{Solution:-}}$

• Let the numbers be x and y.

→ x = 4y …..equ(¡)

→ $\sf \large\frac{(21+x)}{(y+21)}= \frac{7}{4}$

→ 4 ( 21 + x ) = 7 ( y + 21 )

→ 84 + 4x = 7y + 147

→ 4x - 7y = 147 - 84

→ 4x - 7y = 63 ….. equ(¡¡)

• Substitute value of x from (¡) in (¡¡)

→ 16y - 7y = 9y = 63,

→ y = 7 and x = 28.

$\bf{\underline{Hence:-}}$

• The numbers are 28 and 7.