Question

3) A parallelogram has two sides of lengths 18 cm and 8 cm and the measure of one angle is 60 degrees. Find the area of the parallelogram.

Answer 1

Answer:

area of parallalogram = l×b

=> 18×8

==>144 cm2

Answer 2

Area of parallelogram is 72√3 cm² or 124.70 cm².

Step-by-step explanation:

Given:

• Parallelogram has two sides of lengths 18 cm and 8 cm, and
• The measure of one angle is 60 degrees.

To find:

• Find the area of the parallelogram.

Solution:

Formula to be used:

Area of parallelogram $\bf S = ab \: sin \: \theta$

here, a and b are sides of parallelogram.

Step 1:

Write the given values.

As two sides are given.

Let,

$a = 18 \: cm$

and

$b = 8 \: cm$

one acute angle is given,

$\theta = 60 ^{ \circ}$

Step 2:

Put the values in the formula.

Area of parallelogram

$S = 18 \times 8 \times \sin( {60}^{ \circ} )$

or

$= 18 \times 8 \times \frac{ \sqrt{3} }{2}$

or

$\bf S= 72 \sqrt{3} \: sq - cm$

or

put the value of √3=1.732

$= 72 \times 1.732$

or

$\bf S= 124.70 \: {cm}^{2}$

Thus,

Area of parallelogram is 72√3 cm² or 124.70 cm².

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