Question

3. A particle is at position (3 m, 4 m, 5 m) in space.
Its distance from the origin is
(1) 12 m
(2) 10 m
(38 52 m
(4) 9 m​

Answer 1

Answer:

Let us consider the particle P(3,4,5) and origin O(0,0,0)

=> distance formula =  $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2}$

=> PO =  $\sqrt{(3-0)^2+(4-0)^2+(5-0)^2}$

=> PO = $\sqrt{3^2+4^2+5^2}$ = $\sqrt{9+16+25}$ = $\sqrt{50}$

=> PO = $5\sqrt{2}$ units