Question

3.
A particle is thrown vertically up with initial-
velocity of 60 m/s. The distance covered by the
particle in first two seconds of descent will be
(take g = 10 m/s2)
(1) 5 m
(2) 15 m
(3) 20 m
(4) 40 m

Answer 1

Answer:

2 and.......

Explanation:

of 60 m/s. The distance covered by the

particle in first two seconds of descent will be

(take g = 10 m/s2)

(1) 5 m

(2) 15 m

(3) 20 m

(4) 40 m