3. A particle moves along a path ABCD as shown in the figure. Then the magntidue of net displacement of the particle from position A to D is
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Total displacement s = AD = AC+CD
Given,
CD = 5 m
AB = 4 m
BC = 3 m
In ABC triangle, pythagorean theorem,
So net displacement s = 5 + 5 = 10 m
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