Question

3. A particle of mass 2 kg is moving on a
circular path of radius 10 m with a speed of
5 ms -- and its speed is increasing at rate of
3 ms. Find the force acting on the particle.​

Answer 1

Answer:

m=2kg

r=10m

u=5ms

v=3ms

f=ma

a=u-v/r

a=5-3/10

a=0.2

f=ma

f=2*0.2

f=4.4N

Explanation:

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Answer 2

Given,

Mass of the object (m)=2 kg

The radius of the circular path(r)=10 m

Speed of object(v)=5m/s

Rate of change of speed=3m/s

To find,

Force acting on the particle (F)

Solution,

Using the formula,

Force acting on an object moving on a circular path (F) = $\frac{mv^{2} }{r}$

Substituting the values given, we get

⇒F=$\frac{(2)(5^{2} )}{10}$

⇒F=5N

Hence, the force acting on the object is 5N.