Question

3. A particle of mass m, is kept at x = 0 and another of
mass m, at x = d. When a third particle is kept at
x = d/4, it experiences no net gravitational force due
to the two particles. Find m2/m.​

Answer 1

Answer:

gravitational force an m(3) due to m(1)

f=Gm (1) (3) /(d/4)2

gravitational force on m(3) due to m(2)

F= Gm(2) M(3) /(d-d/4)

ATQ

if ther is no gravitational force

F=F'

or Gm(1) m(3)/(d/4)2=Gm(2)M(3)/(d-d/4)2

m1=m2/9

m1/m2=1/9