3. A picture frame has its length 8 cm longer than its width. It has an inner
1-cm boundary such that a maximum 660 cm2-picture may fit into it. Find
the dimensions of this frame.?
Answers
Given:
A picture frame has its length 8 cm longer than its width.
It has an inner 1-cm boundary such that a maximum 660 cm2-picture may fit into it
To find:
Find the dimensions of this frame?
Solution:
Let's assume,
"L" → the length of the picture frame
"W" → the width of the picture frame
Since the picture frame has its length 8 cm longer than its width, so we can form an equation as,
L = W + 8
The picture frame has an inner boundary of 1 cm, so,
The length of the picture = [L - (2×1)] = [W + 8 - 2] = [W + 6]
The width of the picture = [W - (2×1)] = [W - 2]
The area of the picture which may fit into the frame = 660 cm²
We know the formula of the area of the rectangle is,
Therefore, we can form an equation as,
[Length of the picture] × [Width of the picture] = [Area of the picture]
the value of width cannot be negative, so ignoring the negative value
← width of the picture frame
∴ L = W + 8 = 24 + 8 = 32 cm ← length of the picture frame
Thus, the dimension of this picture frame is → 32 cm × 24 cm.
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