Math, asked by emmanloza11, 6 months ago

3. A picture frame has its length 8 cm longer than its width. It has an inner
1-cm boundary such that a maximum 660 cm2-picture may fit into it. Find
the dimensions of this frame.?​

Answers

Answered by bhagyashreechowdhury
5

Given:

A picture frame has its length 8 cm longer than its width.

It has an inner  1-cm boundary such that a maximum 660 cm2-picture may fit into it

To find:

Find  the dimensions of this frame?​

Solution:

Let's assume,

"L" → the length of the picture frame

"W" → the width of the picture frame

Since the picture frame has its length 8 cm longer than its width, so we can form an equation as,

L = W + 8

The picture frame has an inner boundary of 1 cm, so,

The length of the picture = [L - (2×1)] = [W + 8 - 2] = [W + 6]

The width of the picture = [W - (2×1)] = [W - 2]

The area of the picture which may fit into the frame = 660 cm²

We know the formula of the area of the rectangle is,

\boxed{\bold{Area\:of\:the\:rectangle = length \times breadth}}

Therefore, we can form an equation as,

[Length of the picture] × [Width of the picture] = [Area of the picture]

\implies [W+6][W-2] = 660

\implies W^2 + 6W -2W - 12 = 660

\implies W^2 + 4W - 12 = 660

\implies W^2 + 4W - 672 = 0

\implies W^2 - 24W + 28W - 672 = 0

\implies W(W - 24) + 28(W - 24) = 0

\implies (W - 24)(W + 28) = 0

\implies W = 24 \:or\:W = -28

the value of width cannot be negative, so ignoring the negative value

\implies \bold{W = 24\:cm}width of the picture frame

L = W + 8 = 24 + 8 = 32 cmlength of the picture frame

Thus, the dimension of this picture frame is → 32 cm × 24 cm.

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