3. A playground is in the form of a rectangle with two semicircles at its ends. Find the area of the playground.
Answers
Answer:
52.57m2
Step-by-step explanation:
area of play ground = area of rectangle + 2 (area of semi circle)
given ,
length of rectangle l = 10m
breadth of rectangle b = 4m
diameter of semi circle d = 4m
so ,
area of rectangle = l*b
= 10*4
= 40m^(2)
area of 2 semi circles = 2(πd^(2)/8)
= 12.57 m^(2)
therefore area of playground = 40 + 12.57
= 52.57 m^(2)
Step-by-step explanation:
Given l=36m,b=24.5m
⇒ Area of a rectangle =l×b=36×24.5=882m2
⇒ Radius of a semi circle = 224.5
=12.25m
⇒ Area of a semicircle = 2πr 2
= 7×222×(12.25) 2
=235.812m2
⇒ Area of two semi-circle =2×235.812=471.624m2
∴ Area of playground = Area of rectangle + Area of two semi-circle
∴ Area of the playground =(882+471.624)m2=1353.624m2